Optimal. Leaf size=411 \[ \frac{b^{3/2} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{d e^{3/2} \left (b^2-a^2\right )^{5/4}}-\frac{b^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{d e^{3/2} \left (b^2-a^2\right )^{5/4}}-\frac{2 a E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{e \cos (c+d x)}}{d e^2 \left (a^2-b^2\right ) \sqrt{\cos (c+d x)}}-\frac{2 (b-a \sin (c+d x))}{d e \left (a^2-b^2\right ) \sqrt{e \cos (c+d x)}}-\frac{a b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{d e \left (a^2-b^2\right ) \left (b-\sqrt{b^2-a^2}\right ) \sqrt{e \cos (c+d x)}}-\frac{a b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{d e \left (a^2-b^2\right ) \left (\sqrt{b^2-a^2}+b\right ) \sqrt{e \cos (c+d x)}} \]
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Rubi [A] time = 0.928426, antiderivative size = 411, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 11, integrand size = 25, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.44, Rules used = {2696, 2867, 2640, 2639, 2701, 2807, 2805, 329, 298, 205, 208} \[ \frac{b^{3/2} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{d e^{3/2} \left (b^2-a^2\right )^{5/4}}-\frac{b^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt{e} \sqrt [4]{b^2-a^2}}\right )}{d e^{3/2} \left (b^2-a^2\right )^{5/4}}-\frac{2 a E\left (\left .\frac{1}{2} (c+d x)\right |2\right ) \sqrt{e \cos (c+d x)}}{d e^2 \left (a^2-b^2\right ) \sqrt{\cos (c+d x)}}-\frac{2 (b-a \sin (c+d x))}{d e \left (a^2-b^2\right ) \sqrt{e \cos (c+d x)}}-\frac{a b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{d e \left (a^2-b^2\right ) \left (b-\sqrt{b^2-a^2}\right ) \sqrt{e \cos (c+d x)}}-\frac{a b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{b^2-a^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{d e \left (a^2-b^2\right ) \left (\sqrt{b^2-a^2}+b\right ) \sqrt{e \cos (c+d x)}} \]
Antiderivative was successfully verified.
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Rule 2696
Rule 2867
Rule 2640
Rule 2639
Rule 2701
Rule 2807
Rule 2805
Rule 329
Rule 298
Rule 205
Rule 208
Rubi steps
\begin{align*} \int \frac{1}{(e \cos (c+d x))^{3/2} (a+b \sin (c+d x))} \, dx &=-\frac{2 (b-a \sin (c+d x))}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)}}-\frac{2 \int \frac{\sqrt{e \cos (c+d x)} \left (\frac{a^2}{2}+\frac{b^2}{2}+\frac{1}{2} a b \sin (c+d x)\right )}{a+b \sin (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2}\\ &=-\frac{2 (b-a \sin (c+d x))}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)}}-\frac{a \int \sqrt{e \cos (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2}-\frac{b^2 \int \frac{\sqrt{e \cos (c+d x)}}{a+b \sin (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2}\\ &=-\frac{2 (b-a \sin (c+d x))}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)}}+\frac{(a b) \int \frac{1}{\sqrt{e \cos (c+d x)} \left (\sqrt{-a^2+b^2}-b \cos (c+d x)\right )} \, dx}{2 \left (a^2-b^2\right ) e}-\frac{(a b) \int \frac{1}{\sqrt{e \cos (c+d x)} \left (\sqrt{-a^2+b^2}+b \cos (c+d x)\right )} \, dx}{2 \left (a^2-b^2\right ) e}-\frac{b^3 \operatorname{Subst}\left (\int \frac{\sqrt{x}}{\left (a^2-b^2\right ) e^2+b^2 x^2} \, dx,x,e \cos (c+d x)\right )}{\left (a^2-b^2\right ) d e}-\frac{\left (a \sqrt{e \cos (c+d x)}\right ) \int \sqrt{\cos (c+d x)} \, dx}{\left (a^2-b^2\right ) e^2 \sqrt{\cos (c+d x)}}\\ &=-\frac{2 a \sqrt{e \cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{\left (a^2-b^2\right ) d e^2 \sqrt{\cos (c+d x)}}-\frac{2 (b-a \sin (c+d x))}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)}}-\frac{\left (2 b^3\right ) \operatorname{Subst}\left (\int \frac{x^2}{\left (a^2-b^2\right ) e^2+b^2 x^4} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{\left (a^2-b^2\right ) d e}+\frac{\left (a b \sqrt{\cos (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)} \left (\sqrt{-a^2+b^2}-b \cos (c+d x)\right )} \, dx}{2 \left (a^2-b^2\right ) e \sqrt{e \cos (c+d x)}}-\frac{\left (a b \sqrt{\cos (c+d x)}\right ) \int \frac{1}{\sqrt{\cos (c+d x)} \left (\sqrt{-a^2+b^2}+b \cos (c+d x)\right )} \, dx}{2 \left (a^2-b^2\right ) e \sqrt{e \cos (c+d x)}}\\ &=-\frac{2 a \sqrt{e \cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{\left (a^2-b^2\right ) d e^2 \sqrt{\cos (c+d x)}}-\frac{a b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{\left (a^2-b^2\right ) \left (b-\sqrt{-a^2+b^2}\right ) d e \sqrt{e \cos (c+d x)}}-\frac{a b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{\left (a^2-b^2\right ) \left (b+\sqrt{-a^2+b^2}\right ) d e \sqrt{e \cos (c+d x)}}-\frac{2 (b-a \sin (c+d x))}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)}}+\frac{b^2 \operatorname{Subst}\left (\int \frac{1}{\sqrt{-a^2+b^2} e-b x^2} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{\left (a^2-b^2\right ) d e}-\frac{b^2 \operatorname{Subst}\left (\int \frac{1}{\sqrt{-a^2+b^2} e+b x^2} \, dx,x,\sqrt{e \cos (c+d x)}\right )}{\left (a^2-b^2\right ) d e}\\ &=\frac{b^{3/2} \tan ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt{e}}\right )}{\left (-a^2+b^2\right )^{5/4} d e^{3/2}}-\frac{b^{3/2} \tanh ^{-1}\left (\frac{\sqrt{b} \sqrt{e \cos (c+d x)}}{\sqrt [4]{-a^2+b^2} \sqrt{e}}\right )}{\left (-a^2+b^2\right )^{5/4} d e^{3/2}}-\frac{2 a \sqrt{e \cos (c+d x)} E\left (\left .\frac{1}{2} (c+d x)\right |2\right )}{\left (a^2-b^2\right ) d e^2 \sqrt{\cos (c+d x)}}-\frac{a b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b-\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{\left (a^2-b^2\right ) \left (b-\sqrt{-a^2+b^2}\right ) d e \sqrt{e \cos (c+d x)}}-\frac{a b \sqrt{\cos (c+d x)} \Pi \left (\frac{2 b}{b+\sqrt{-a^2+b^2}};\left .\frac{1}{2} (c+d x)\right |2\right )}{\left (a^2-b^2\right ) \left (b+\sqrt{-a^2+b^2}\right ) d e \sqrt{e \cos (c+d x)}}-\frac{2 (b-a \sin (c+d x))}{\left (a^2-b^2\right ) d e \sqrt{e \cos (c+d x)}}\\ \end{align*}
Mathematica [C] time = 21.7726, size = 791, normalized size = 1.92 \[ \frac{2 \cos (c+d x) (a \sin (c+d x)-b)}{d \left (a^2-b^2\right ) (e \cos (c+d x))^{3/2}}-\frac{\cos ^{\frac{3}{2}}(c+d x) \left (-\frac{a \sin ^2(c+d x) \left (a+b \sqrt{1-\cos ^2(c+d x)}\right ) \left (8 b^{5/2} \cos ^{\frac{3}{2}}(c+d x) F_1\left (\frac{3}{4};-\frac{1}{2},1;\frac{7}{4};\cos ^2(c+d x),\frac{b^2 \cos ^2(c+d x)}{b^2-a^2}\right )+3 \sqrt{2} a \left (a^2-b^2\right )^{3/4} \left (-\log \left (-\sqrt{2} \sqrt{b} \sqrt [4]{a^2-b^2} \sqrt{\cos (c+d x)}+\sqrt{a^2-b^2}+b \cos (c+d x)\right )+\log \left (\sqrt{2} \sqrt{b} \sqrt [4]{a^2-b^2} \sqrt{\cos (c+d x)}+\sqrt{a^2-b^2}+b \cos (c+d x)\right )+2 \tan ^{-1}\left (1-\frac{\sqrt{2} \sqrt{b} \sqrt{\cos (c+d x)}}{\sqrt [4]{a^2-b^2}}\right )-2 \tan ^{-1}\left (\frac{\sqrt{2} \sqrt{b} \sqrt{\cos (c+d x)}}{\sqrt [4]{a^2-b^2}}+1\right )\right )\right )}{12 \sqrt{b} \left (b^2-a^2\right ) \left (1-\cos ^2(c+d x)\right ) (a+b \sin (c+d x))}-\frac{2 \left (a^2+b^2\right ) \sin (c+d x) \left (a+b \sqrt{1-\cos ^2(c+d x)}\right ) \left (\frac{a \cos ^{\frac{3}{2}}(c+d x) F_1\left (\frac{3}{4};\frac{1}{2},1;\frac{7}{4};\cos ^2(c+d x),\frac{b^2 \cos ^2(c+d x)}{b^2-a^2}\right )}{3 \left (a^2-b^2\right )}+\frac{\left (\frac{1}{8}+\frac{i}{8}\right ) \left (-\log \left (-(1+i) \sqrt{b} \sqrt [4]{b^2-a^2} \sqrt{\cos (c+d x)}+\sqrt{b^2-a^2}+i b \cos (c+d x)\right )+\log \left ((1+i) \sqrt{b} \sqrt [4]{b^2-a^2} \sqrt{\cos (c+d x)}+\sqrt{b^2-a^2}+i b \cos (c+d x)\right )+2 \tan ^{-1}\left (1-\frac{(1+i) \sqrt{b} \sqrt{\cos (c+d x)}}{\sqrt [4]{b^2-a^2}}\right )-2 \tan ^{-1}\left (1+\frac{(1+i) \sqrt{b} \sqrt{\cos (c+d x)}}{\sqrt [4]{b^2-a^2}}\right )\right )}{\sqrt{b} \sqrt [4]{b^2-a^2}}\right )}{\sqrt{1-\cos ^2(c+d x)} (a+b \sin (c+d x))}\right )}{d (a-b) (a+b) (e \cos (c+d x))^{3/2}} \]
Warning: Unable to verify antiderivative.
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Maple [C] time = 3.057, size = 1103, normalized size = 2.7 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (e \cos \left (d x + c\right )\right )^{\frac{3}{2}}{\left (b \sin \left (d x + c\right ) + a\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{1}{\left (e \cos \left (d x + c\right )\right )^{\frac{3}{2}}{\left (b \sin \left (d x + c\right ) + a\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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